I have just purchased a Schumacher XP2260 Power Source (Jump Starter) so that I can always start my motorhome. I try to run the motorhome regularly in order to keep the battery charged but, I often forget to do this. The jump starter will allow me to jump start the motor home or any other vehicle I need it for.
However, this unit has an inverter with two A/C outputs. I wonder if I could use this to power a studio strobe such as my White Ligtning WL5000 outdoors. The problem is that I cannot figure out the power requirements for the strobe.
Here is the electrical info for the WL5000
Powering: 120VAC, 50/60HZ, 2A
Maximum Power: 250 wattseconds in the WL 10,000 units, and 130 wattseconds in the WL
5,000 units
Controls: Full Power, 2/3 Power, 1/3 Power, and Test/Discharge
Modeling Lamp: 100w household max. (indicates recycle status)
I don't plan to use the modeling light)
Recycle Time: 3/2/1 seconds in the WL 10,000 units, and 1.5/1/0.5 seconds in the WL 5,000
units
Here is some information from various sources regarding the inverters' capability
Built-in 400 Watt power inverter for 120V AC household power •
This unit has an 18 amp hour internal battery. It can power a device drawing 110 watts for about 1.5 hours,
The Instant Power™ must be used with devices drawing 200 watts or less. Ifthe wattage is not marked on the device, use only devices that draw less than 1.7 Ampsof AC current.
It is recommended that you don't use this to power
1.
Switch Mode Power Supplies
2.
Linear Power Supplies
3.
Class 2 Transformers
4.
Line Filter Capacitors
5.
Shaded Pole Motors
6.
Fan Motors
7.
Microwave Ovens
8.
Fluorescent and High Intensity Lamps (with a ballast)
9.
Transformerless Battery Charger
I realize that in talking watts and watt seconds, we are talking apples and oranges...
I don't want to hurt either the new power supply or my old WL5000 units. Otherwise, I'd just plug one or two units in and try it...